if m<ACD = 120 - x m<B = 60 and m<A= 10 + x find m<ACB

Answer 1

To find the measure of angle ACB, we can use the fact that the sum of the angles in a triangle is always 180 degrees.

We know that angle ACD = 120 - x, angle B = 60, angle A = 10 + x.

So, angle ACB = 180 - (angle ACD + angle B)
angle ACB = 180 - (120 - x + 60)
angle ACB = 180 - (180 - x)
angle ACB = x

Therefore, the measure of angle ACB is x.