If m varies directly as n and in versely as the square of p having a value of m=2 and p=1 k constant

Answer 1

To express this relationship in equation form, we can write:

m = k*n/p^2

Given that m = 2 and p = 1, we can substitute these values into the equation:

2 = k*n/1^2
2 = k*n

Since k is a constant, we can solve for k by setting n = 1:

2 = k*1
k = 2

Therefore, the constant k is equal to 2, and the equation for the relationship is:

m = 2n/p^2