If logx≈0.698, what is log(x⋅x⋅x)

Question

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Answer 1

To find \(\log(x \cdot x \cdot x)\), we can start by rewriting it in terms of logarithms.

First, we recognize that:

\[ x \cdot x \cdot x = x^3 \]

Now, we can apply the logarithmic identity \(\log(a^b) = b \log(a)\). Therefore, we have:

\[ \log(x^3) = 3 \log(x) \]

Given that \(\log(x) \approx 0.698\), we can substitute this value into our equation:

\[ \log(x^3) = 3 \cdot 0.698 \]

Now, we perform the multiplication:

\[ 3 \cdot 0.698 = 2.094 \]

Thus, we find:

\[ \log(x \cdot x \cdot x) \approx 2.094 \]

So, the answer is \(\boxed{2.094}\).