To find \( \log_{10} 72 \), we can use the properties of logarithms, specifically the multiplication rule:
\[ \log(ab) = \log a + \log b \]
First, we can express 72 in terms of numbers for which we already have logarithm values. Notice that:
\[ 72 = 8 \times 9 = 2^3 \times 3^2 \]
We can also break this down into:
\[ 72 = 18 \times 4 \]
Now we can use the logarithm values provided:
- \( \log 18 \approx 1.2553 \)
- \( \log 4 \approx 0.6021 \)
Using the multiplication rule:
\[ \log 72 = \log(18 \times 4) = \log 18 + \log 4 \]
Now substituting the values:
\[ \log 72 \approx 1.2553 + 0.6021 \approx 1.8574 \]
Thus, the value of \( \log_{10} 72 \) is approximately:
\[ \log 72 \approx 1.8574 \]
So the correct answer is:
log72≈1.8574