If log(base10)of 2 =0.301 and log(base10) of 3 = 0.477, how would I find

a) log(base10) of 8
b) log(base10) of 12
c) log(base10) of 15

1 answer

(a) log(base10) of 8
log(base10) of 8 can be rewritten as
= log(base10) of (2^3)
= 3*[ log(base10) of 2 ]
= 3*0.301
= 0.903

(b) log(base10) of 12
log(base10) of 12 can be rewritten as
= log(base10) of (2*2*3)
= log(base10) of 2 + log(base10) of 2 + log(base10) of 3
= 0.301 + 0.301 + 0.477
= 1.079

(c) log(base10) of 15
log(base10) of 15 can be rewritten as
= log(base10) of (3*5)
= log(base10) of 3 + log(base10) of 5
= log(base10) of 3 + log(base10) of (10/2)
= 0.477 + log(base10) of 10 - log(base10) of 2
= 0.477 + 1 - 0.301
= 1.176

hope this helps~ :)
Similar Questions
  1. Solve each of the following 8-bit subtractionproblems using 2’s complement representation: i. 011111112 - 78 base10 ii.
    1. answers icon 2 answers
  2. Verify these answers please.1. Which of the following functions would f(x) = log(base 10)x horizontally 4 units to the left? a)
    1. answers icon 0 answers
  3. (1).Write the eight-bit 2’s complementrepresentation of (-23) base10 (2).What is the first thing you must do in order to
    1. answers icon 1 answer
  4. log(base 10)(x+5)+2log(base10)log(base10)(x+5(10 to the 2nd power) log(base10)(100x+500) I love you china.
    1. answers icon 1 answer
more similar questions