If line k*+2y-3=0 passes through point (-5,9) then k=

Question

Is that k*x+2y-3=0 ?
If so, then substitute -5 for x and 9 for y to get
-5*k + 2*9 - 3 =0 and solve for k.

Nevermind. I am unable to comprehend this on the computer. I will ask someone to do it on paper for me. Thank-you.