If limit n->∞ Σ (from n=1 to n) of "a sub k" exists and has a finite value, the infinite series Σ (from n=1 to n) of "a sub k"

a) unbounded
b) convergent
c) increasing -----> my answer. Can you check for me, pls? Thanks
d) divergent

1 answer

nope. the terms might be negative.
But if the infinite sum exists and is finite, the partial sums converge to that value.

and if the terms are a sub k, then the sum is Σ (from k=1 to n)
Similar Questions
  1. limit of (x*(y-1)^2*cosx)/(x^2+2(y-1)^2) as (x,y)->(0,1).By evaluating along different paths this limit often goes to 0. This
    1. answers icon 0 answers
  2. (a) Find the number c such that the limit below exists.Limit as x goes to -2 of: x^2+cx=c-3/x^2+2x (b) Calculate the limit for
    1. answers icon 0 answers
  3. (a) Find the number c such that the limit below exists.Limit as x goes to -2 of: x^2+cx=c-3/x^2+2x (b) Calculate the limit for
    1. answers icon 1 answer
  4. limit of (x,y)--->(1,0) of ln(1+y^2/x^2+xy))Find the limit, if it exists, or show that the limit does not exist.
    1. answers icon 0 answers
more similar questions