Asked by manjula
                if (l1,m1,n1),(l2,m2,n2),(l3,m3,n3) are the direction cosines of three mutual perpendicular lines,show that the line whose direction ratios area l1+l2+l3,m1+m2+m3,n1+n2+n3 make equal angles with them
            
            
        Answers
                    Answered by
            drwls
            
    Because the first three lines are mutually perpendicular, dot products of pairs of lines are zero.
l1*l2+m1*m2+n1*n2 = 0
l2*l3+m2*m3+n2*n3 = 0
l1*l3+m1*m3+n1*n3 = 0
Finally, using the above equations, and another dot product, show that the cosine of the angle between the fourth vector and any of the first three vectors is the same.
    
l1*l2+m1*m2+n1*n2 = 0
l2*l3+m2*m3+n2*n3 = 0
l1*l3+m1*m3+n1*n3 = 0
Finally, using the above equations, and another dot product, show that the cosine of the angle between the fourth vector and any of the first three vectors is the same.
                    Answered by
            DIPRA
            
    listen to me dear.solve these six equations.l1l2+m1m2+n1n2=0,l2l3+m2m3+n2n3=0and l1l3+m1m3+n1n3=0...with these solve theselil2+m1m2+n1n2=l2l3+m2m3+n2n3=l1l3+m1m3+n1n3
    
                    Answered by
            fe
            
    hi good answers boys,all are correct
    
                    Answered by
            fe
            
    i will post the correct answer in 2020 without fail
    
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