If Kc = 6.38 × 105 for the reaction

A(g) ⇀ ↽ 2B(g),
what is Kc for the reaction written as
2B(g) ⇀ ↽ A(g)?

How would I solve this?

1 answer

A--> 2B Kc
2B --> A K'c = 1/Kc
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