Specific heat = q / (m * ΔT)
Specific heat = 37.0 cal / (18.0 g * 9.50 °C)
Specific heat = 0.217 cal/(g°C) or 0.217 J/(g°C) (since 1 cal = 4.184 J)
Therefore, the specific heat of the substance is 0.217 cal/(g°C)
If it takes 37.0 calories of heat to raise the temperature of 18.0 g of a substance 9.50 °C, what is the specific heat of the substance? Be sure your answer has
the correct number of significant figures.
Specific heat =
cal
g.℃
1 answer
1 answer