If it takes 37.0 calories of heat to raise the temperature of 17.6 of a substance 9.50 , what is the specific heat of the substance? Be sure your answer has the correct number of significant figures. specific heat= cal/g.0C

Answer 1

To find the specific heat of the substance, we can use the formula:

Q = mcΔT

Where:
Q = heat added (37.0 cal)
m = mass of the substance (17.6 g)
c = specific heat of the substance (to be determined)
ΔT = change in temperature (9.50 °C)

Plugging in the values:

37.0 = 17.6 * c * 9.50

Solving for c:

c = 37.0 / (17.6 * 9.50)
c = 0.2240 cal/g°C

Therefore, the specific heat of the substance is 0.2240 cal/g°C.