Did you make a typo? Is that 41 g, 41.41, or some other number? I know you made a typo in the reaction.
#1. There is no arrow.
#2. There is no CO2 shown.
Balance the equation.
2C4H10 + 13O2 ==> 8CO2 + 10H2O.
mols C4H10 = grams/molar mass.
Using the coefficients in the balanced equation, convert mols C4H10 to mols CO2.
Convert mols CO2 to g. grams = mols x molar mass. This is the theoretical yield.
%yield (actual grams CO2/theoretical yield)*100 =
If, in the reaction below, 31 g of C4H10 produces 41 41 g of CO2, what is the percent yield? Assume that the one reactant is limiting. 2C4H10 + 13O2 + 10H2O
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