Put the equation into the form
ax^2 + bx + c = 0
then use the quadratic formula to find the solutions.
If i'm given the equation
4.23= -.19t^2+2.56t-2.37
how do i find the value of t?
2 answers
Rewrite it in standard quadratic form as:
0.19t^2 - 2.56 t +6.60 = 0
The coefficients and constant are:
a = 0.19
b = -2.56
c = 6.6
Then use the quadratic formula for the two roots:
t = [-b +/1 sqrt(b^2-4ac)]/2a
One of the solutions is exactly 10.
The other is 3.4737
0.19t^2 - 2.56 t +6.60 = 0
The coefficients and constant are:
a = 0.19
b = -2.56
c = 6.6
Then use the quadratic formula for the two roots:
t = [-b +/1 sqrt(b^2-4ac)]/2a
One of the solutions is exactly 10.
The other is 3.4737
1 answer