If i'm given the equation

4.23= -.19t^2+2.56t-2.37

how do i find the value of t?

2 answers

Put the equation into the form
ax^2 + bx + c = 0
then use the quadratic formula to find the solutions.
Rewrite it in standard quadratic form as:
0.19t^2 - 2.56 t +6.60 = 0

The coefficients and constant are:
a = 0.19
b = -2.56
c = 6.6

Then use the quadratic formula for the two roots:

t = [-b +/1 sqrt(b^2-4ac)]/2a

One of the solutions is exactly 10.
The other is 3.4737
Similar Questions
  1. N 5 22x2 1 76x 1 430Use the equation to find N for each year in the table. (b) Discuss how well this equation approximates the
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. 1. Find the equation of the asymptotic of the hyperbolex^2/9 - y^2/ 4 = 1. 2. Given the equation of a function 2x^2 + 5y^2 - 16x
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions