If I have cyclohexene in a hydroboration-oxidation reaction to form cyclohexanol how can I find percentage yield?

I have NaBH4 (0.0610) and boron triflouride etherate (0.0162) and they are in a 4 to 3 ratio to form b2h6 (diborane) so diborane number of moles is based on boron triflouride etherate as its the limiting reagent so then I plug in to the overall reaction 3cyclohexene (0.0594mol) + b2h6 to form 3cyclohexanol. so according to the overall reaction b2h6 is the limiting reagent so will use that to form cyclohexanol using ratio 1:3?

1 answer

% yield = (actual yield/theoretical yield)*100 = ?
The actual yield is what the problem tells you the reaction produces. The theoretical yield is what you calculate is formed from the stoichiometry.