If I have a 1.9 multiple gas held at pressure at 5 AM and in the container with a volume of 50 l what is the temperature gas

Answer 1

To determine the temperature of the gas, we need to use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in L)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)

First, we need to convert the pressure to atm by dividing the multiple gas held at pressure by 1.0 atm. So, 1.9 multiple gas = 1.9 atm.

Now we can plug in the values we have:

1.9 atm * 50 L = n * 0.0821 L.atm/mol.K * T

Solving for n:

95 = n * 0.0821 * T

n = 95 / (0.0821 * T)

Given that the molar mass of an ideal gas at STP is around 22.414 l/mol, we can approximate the number of moles (n) to be 2 moles. So:

2 = 0.0821 * T

T = 2 / 0.0821
T ≈ 24.37 K

Therefore, the temperature of the gas in the container at 5 AM with a volume of 50 L and a pressure of 1.9 atm is approximately 24.37 K.