If I have 2.5L of propane at STP, how many grams of water can be produced by this combustion?

5 answers

I know STP is 22.4 L, but I need more help
so, you have 2.5/22.4 = 0.1116 moles of propane
Now look at the reaction equation for the combustion to see how many moles of water that will produce
then convert that to grams
Ok so this is the equation:

C3H8 + 5O2 = 3CO2 + 4H2O

What do I have to do next?
So you have 0.1116 mols propane. According to your balanced equation, 1 mol C3H8 will produce 4 mols H2O. That means 0.1116 mols C3H8 will produce .......mols H2O.
Ahh, I get it now thank you