If I have 1.9 mol of gas held at a pressure of 5 ATM and in a container with a volume of 50 l what is the temperature of gas

Answer 1

To find the temperature of the gas, we can use the ideal gas law formula: PV = nRT, where:

P = pressure (5 atm)
V = volume (50 L)
n = moles of gas (1.9 mol)
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin

First, we need to convert the pressure from atm to atm/L, by dividing by the volume:

5 atm / 50 L = 0.1 atm/L

Now, plug in the values into the ideal gas law equation:

5 atm * 50 L = 1.9 mol * 0.0821 L.atm/mol.K * T

250 L.atm = 0.15599 mol.K * T

T = 250 L.atm / 0.15599 mol.K
T = 1601.7 K

Therefore, the temperature of the gas is 1601.7 Kelvin.