If he travel 7km 40° west northern 10km east find the ressultant
2 answers
Need calaculation step by step
Not sure what direction "west northern" is, but I'll assume 40° west of north. That would make the x-y components
(-7sin40°,7cos40°) = (-4.50,5.36)
10 east = (10,0)
The resultant distance is √(5.50^2 + 5.36^2) = 7.68
The angle θ from due east is
tanθ = y/x = 5.36/5.50 = 0.97
θ = 44° so the direction is
E44°N or N46°E
(-7sin40°,7cos40°) = (-4.50,5.36)
10 east = (10,0)
The resultant distance is √(5.50^2 + 5.36^2) = 7.68
The angle θ from due east is
tanθ = y/x = 5.36/5.50 = 0.97
θ = 44° so the direction is
E44°N or N46°E