if h(x)= (the antiderivative of) 2x^2 +8x-5 dx

find h'(x)

3 answers

What is the derivative of the antiderivative?

(what is the square root of the square of a number)?
o so it is 2x^2 +8x-5 dx ... thanks!
wait isn't it 4x+8
cause you still didn't find the derivative of the antiderivative you just reposted the antiderivative