x = csc y = 1/sin y
sin y = 1/x
y = sin^-1(1/x)
If h(x) = csc(x), find the inverse h^(-1)(x).
express answer in terms of sin^(-1),
cos^(-1)
or tan^(-1)
Don't know where to start -
1 answer
express answer in terms of sin^(-1),
cos^(-1)
or tan^(-1)
Don't know where to start -
1 answer