Asked by Lin
If given the ratio of temperatures in Celsius to Kelvin for Gold to silver as 1.10614 to 1.08265. How can I find the temperatures of each individual element form just this information?
Answers
Answered by
drwls
A Celsius temperature is always lower than a Kelvin temperature, at the same temperature. For example, 100 C = 373 K.
So how can the ratio of T(C) to T(K) be greater than 1?
It is unclear if your ratios are T(C)/T(K) or T(gold)/T(silver) using a given scale.
Make sure you are stating the problem correctly
So how can the ratio of T(C) to T(K) be greater than 1?
It is unclear if your ratios are T(C)/T(K) or T(gold)/T(silver) using a given scale.
Make sure you are stating the problem correctly
Answered by
MathMate
After a little checking, I believe the question is meant to be:
"If given the ratios of melting points of Gold <b>and</b> silver <b>are</b> 1.10614 in Celsius<b>, and</b> 1.08265 <b>in Kelvin</b>. How can I find the <b>melting points</b> of each individual element from just this information?"
Let
S=melting point of silver in Celsius, and
G=melting point of gold in Celsius, then
G/S = 1.10614
(G+273.15)/(S+273.15)=1.08265
Cross multiply each equation and solve for G and S.
G=1.10614S...(1)
G+273.15=1.08265(S+273.15)...(2)
Eliminate G by subtracting (2) from (1)
(1.10614-1.08265)S=(1.08265-1)273.15
S=22.576/0.02349
=961.08 °C
G=1.10614*961.08
=1063.09°C
"If given the ratios of melting points of Gold <b>and</b> silver <b>are</b> 1.10614 in Celsius<b>, and</b> 1.08265 <b>in Kelvin</b>. How can I find the <b>melting points</b> of each individual element from just this information?"
Let
S=melting point of silver in Celsius, and
G=melting point of gold in Celsius, then
G/S = 1.10614
(G+273.15)/(S+273.15)=1.08265
Cross multiply each equation and solve for G and S.
G=1.10614S...(1)
G+273.15=1.08265(S+273.15)...(2)
Eliminate G by subtracting (2) from (1)
(1.10614-1.08265)S=(1.08265-1)273.15
S=22.576/0.02349
=961.08 °C
G=1.10614*961.08
=1063.09°C
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