if g(x) varies exponentially with x, and g(0) =37 and g(7) =5940 find the particular equation...

Answer 1

g = ka^x
37 = ka^0 = k
so, g = 37a^x
5940 = 37a^7
160.54 = a^7
a = 2.066

g = 37*2.066^x