If your expression mean:
g = a ∙ x ∙√ ( 1 - x )²
then
g(10) = a ∙ 10 ∙ √ ( 1 - 10 )² = 10 a ∙ √ ( - 9 )² = 10 a ∙ ( - 9 ) = - 90 a
If g(x)=(ax square root of 1-x)^2. Express g(10) in simplest form
I did g(10)=(a(10) square root 1-10)^2= (a*10)^2(1-10)=1000^2(-9)=
-9000^2
Is this correct? thanks for checking my work
4 answers
g = [ a ∙ x ∙√ ( 1 - x ) ]²
then
g = [ a ∙ 10 ∙√ ( 1 - 10 ) ]² =
[ 10 a ∙√- 9 ) ]² =
( 10 a ∙ 3 i ² )=
(30 a ∙ i )² =
30² ∙ a² ∙ i² =
900 ∙ a² ∙ ( - 1 ) = - 900 ∙ a²
then
g = [ a ∙ 10 ∙√ ( 1 - 10 ) ]² =
[ 10 a ∙√- 9 ) ]² =
( 10 a ∙ 3 i ² )=
(30 a ∙ i )² =
30² ∙ a² ∙ i² =
900 ∙ a² ∙ ( - 1 ) = - 900 ∙ a²
My typo
not
( 10 a ∙ 3 i ² )=
correct is
( 10 a ∙ 3 i )² =
not
( 10 a ∙ 3 i ² )=
correct is
( 10 a ∙ 3 i )² =
yes , it was the second one and when I looked over it again I saw that I actually wrote 100a^2 on my paper but when I put in the question here I did 1000, I can't read my own handwriting. Thank you for explaining both ways.