if g(t)=4+square root of 9-t, what is the smallest possible value of g(t)
A) 0
B) 3
C) 4
D) 5
E) 9
3 answers
clearly the smallest value is 4 which is choice C)
why is the smallest value 4?
your equation was
g(t) = 4 + √(9-t)
you already had 4 and you are adding more to it (the √(9-t)), so g(t) can only become larger since by definition the √ of a number yields a positive result.
So when t=9 you would have
g(t) = 4 + 0
= 4
(the smallest value I can ADD to anything is zero)
g(t) = 4 + √(9-t)
you already had 4 and you are adding more to it (the √(9-t)), so g(t) can only become larger since by definition the √ of a number yields a positive result.
So when t=9 you would have
g(t) = 4 + 0
= 4
(the smallest value I can ADD to anything is zero)
3 answers