In the right triangle \( FCH \), you have \( FC = 33 \) cm and \( CH = 13 \) cm with a right angle at \( H \). To find the length of \( FH \), you can use the Pythagorean theorem, which states:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the hypotenuse, and \( a \) and \( b \) are the other two sides. In this case:
- \( a = FH \)
- \( b = CH = 13 \) cm
- \( c = FC = 33 \) cm
Thus, the equation becomes:
\[ FH^2 + 13^2 = 33^2 \]
Calculating \( 13^2 \) and \( 33^2 \):
\[ 13^2 = 169 \] \[ 33^2 = 1089 \]
So the equation is:
\[ FH^2 + 169 = 1089 \]
Now, subtract \( 169 \) from both sides:
\[ FH^2 = 1089 - 169 \] \[ FH^2 = 920 \]
Now, take the square root of both sides to find \( FH \):
\[ FH = \sqrt{920} \]
Calculating the square root of \( 920 \):
\[ FH \approx 30.33 , \text{cm} \]
Therefore, the length of \( FH \) is approximately \( 30.33 , \text{cm} \).