assuming you are using the [..] operator to have the same meaning as (..)
we have
Limit x^2/sinx , as x ---> 0
using L'Hopitals Rule
lim x^2/sinx
= lim 2x/cosx , as x --->
= 0/1
= 0
verification:
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2%2Fsinx
looks at x = 0,
the function has a value of 0 , the origin (0,0)
If [ ... ] is some other mathematical operator, define it please
if
f(x)=x[x]/sin[x]
then show that lim f(x)has no existence
x>0
2 answers
as an example....
[2.32]=2
[2.32]=2
1 answer