If f(x) = (x/8)^2, what is f(-4)?

Answer 1

To find \( f(-4) \) for the function \( f(x) = \left(\frac{x}{8}\right)^2 \), we will substitute \(-4\) into the function.

1. Substitute \( x = -4 \): \[ f(-4) = \left(\frac{-4}{8}\right)^2 \]

2. Simplify the fraction: \[ \frac{-4}{8} = -\frac{1}{2} \]

3. Now, square the value: \[ f(-4) = \left(-\frac{1}{2}\right)^2 = \frac{1}{4} \]

Thus, the final result is: \[ f(-4) = \frac{1}{4} \]