f*g = (x+4)(x-4) = x^2 -16
b) y = x^2 - 16
x^2 is always >/= 0
so smallest y is -16
If f(x)=x+4 and g(x)=x-4
a)Find an expression for (f*g)(x)?
b)what is the minimum value of the function (f*g)(x)
I used the * sign for a times symbol.
1 answer