If f = √u, f' = u' / 2√u.
You have u=3x, so
f'(x) = 3 / 2√(3x)
f'(3) = 3 / 2√9 = 1/2
If f(x)=the sqrt of 3x,find f'(3).
Isn't it 3/2•sqrt of 3?
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Isn't it 3/2•sqrt of 3?
1 answer
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1 answer