if f(x) = square root of e^2x +1, then then f'(0) equals what?

Answer 1

f(x) = [e^2x + 1]^(1/2)
df/dx = [(1/2)/sqrt[e^2x + 1]* 2*e^2x = e^2x / sqrt[e^2x + 1]
= 1/sqrt2 at t = 0