To find the domain of the inverse function \( f^{-1}(x) \), we first need to determine the range of the original function \( f(x) = \log_2(x+2) \).
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Identify the domain of \( f(x) \): The function \( f(x) \) is defined for \( x + 2 > 0 \) (since the logarithm is only defined for positive arguments). This means: \[ x > -2 \] So, the domain of \( f(x) \) is \( (-2, \infty) \).
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Determine the range of \( f(x) \): As \( x \) approaches \( -2 \) from the right, \( f(x) = \log_2(x+2) \) approaches \( \log_2(0) \), which is \( -\infty \). As \( x \) approaches \( \infty \), \( f(x) \) approaches \( \infty \).
Therefore, the range of \( f(x) \) is: \[ (-\infty, \infty) \]
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Find the domain of \( f^{-1}(x) \): The domain of the inverse function \( f^{-1}(x) \) is equal to the range of the original function \( f(x) \).
Thus, the domain of \( f^{-1}(x) \) is \( (-\infty, \infty) \).
The correct option is: (−∞,∞)