f'(x) = (x^2)^2 (2x) - x^2 (1)
= 2x^5-x^2
Google
differentiation under the integral
for several explanations. Wikipedia has a good article.
This is really just the chain rule in reverse.
If f(x) = integrate t^2 from x to x^2, then
f'(x)=
f'(-1)=
Please help! I have no idea how to approach this.
1 answer