If f(x)=e^x, g(x)=sin(x), and

h(x)=f(g(x)), then h'(pi/2)=?

Please help I have no idea how to solve

2 answers

I just did this a little while ago
h = e^sin x
h' = cos x e^sin x
cos pi/2 = 0
sin pi/2 = 1
so
0 * 1 = 0
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