If f(x)=e^x, g(x)=sin(x), and
h(x)=f(g(x)), then h'(pi/2)=?
Please help I have no idea how to solve
2 answers
I just did this a little while ago
h = e^sin x
h' = cos x e^sin x
cos pi/2 = 0
sin pi/2 = 1
so
0 * 1 = 0
h' = cos x e^sin x
cos pi/2 = 0
sin pi/2 = 1
so
0 * 1 = 0