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If f(x) and g(x) are differentiable and lim(x->a) f(x)/g(x) exists, does it follow that lim(x->a) f '(x)/g'(x) exists (a converse to l'Hopital's Rule)?
13 years ago

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If f(x) and g(x) are differentiable and lim(x->a) f(x)/g(x) exists, does it follow that lim(x->a) f '(x)/g'(x) exists (a converse to l'Hopital's Rule)?

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