If f(x)=4-coshx/3+coshx,

f'(x)=?

2 answers

If you mean f(x)= (4-coshx)/(3+coshx),
Let u = 4 - coshx and v = 3 + coshx
u' = -sinhx v' = sinhx
f'(x) = (v u'- u v')/(v^2)
Finish it by substution
Got it. Thanks!