let y = (3x)^(3x)
take ln of both sides
ln y = ln (3x)^(3x)
ln y = 3x ln 3x
(dy/dx) / y = 3x(1/x) + 3ln(3x)
dy/dx = (3 + 3ln(3x)) (3x)^(3x)
If f(x)= (3x)^(3x), then f'(x) = ?
Thank you!
1 answer
Thank you!
1 answer