If f'(x) = 3x^2 + 2x and f(2) = 3

Question

Then f(1) = ???

Answer 1

integrate
f(x) = x^3 + x^2 + c
put in point to find constant c
3 = 8 + 4 + c
so
c = 3-12 = -9
f(1) = 1^3 + 1^2 - 9
= -7