Asked by Anonymous
IF
f(x) = {(3,5), (2,4), (1,7)}
h(x)= {(3,2), (4,3), (1,6)}
determine each of the following:
(f+h)(1)=
how do I add f and h?
(f o h)(3)=
how would I multiply f and h?
f^-1(x)=
how would I find the inverse of f?
1/f(x)=
how would I do that?
f(1) = 7 and h(1) = 6
(f + h)(x) is by definition f(x) + h(x)
(f o h)(x) is by definition f(h(x))
h(3) = 2
and f(h(3)) = f(2) = 4
So (foh)(3) = 4
f^(-1)(f(x)) = x by definition.
f(x) = {(3,5), (2,4), (1,7)}
If you take, e.g., x = 3, then you see that
f^(-1)(5) = 3. So, you see that you just need to interchanbge the numbers:
f^(-1)(x) = {(5,3), (4,2), (7,1)}
f(x) = {(3,5), (2,4), (1,7)}
h(x)= {(3,2), (4,3), (1,6)}
determine each of the following:
(f+h)(1)=
how do I add f and h?
(f o h)(3)=
how would I multiply f and h?
f^-1(x)=
how would I find the inverse of f?
1/f(x)=
how would I do that?
f(1) = 7 and h(1) = 6
(f + h)(x) is by definition f(x) + h(x)
(f o h)(x) is by definition f(h(x))
h(3) = 2
and f(h(3)) = f(2) = 4
So (foh)(3) = 4
f^(-1)(f(x)) = x by definition.
f(x) = {(3,5), (2,4), (1,7)}
If you take, e.g., x = 3, then you see that
f^(-1)(5) = 3. So, you see that you just need to interchanbge the numbers:
f^(-1)(x) = {(5,3), (4,2), (7,1)}
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