To find \((f + g)(x)\), you need to add the functions \(f(x)\) and \(g(x)\) together.
You have:
- \(f(x) = 2x - 1\)
- \(g(x) = x^2 - 3x - 2\)
Now, add \(f(x)\) and \(g(x)\):
\[ (f + g)(x) = f(x) + g(x) \]
Substituting the expressions for \(f(x)\) and \(g(x)\):
\[ (f + g)(x) = (2x - 1) + (x^2 - 3x - 2) \]
Combine like terms:
\[ (f + g)(x) = x^2 + (2x - 3x) + (-1 - 2) \] \[ (f + g)(x) = x^2 - x - 3 \]
Thus, the result is:
\[ (f + g)(x) = x^2 - x - 3 \]