If f(x)=2(x-3)^2-5 find the vertex, the x intercepts the y intercepts sketch the graph, choose two points on the graph and find the rate of change

Answer 1

F(x) = Y = 2(x-3)^22(-5
Y = 2(x^2--6x+9)-5
Y = 2x^2-12x+18-5
Y = 2x^2-12x+13

h = -B/2A = 12/4 = 3
k = 2(3-3)^2-5 = -5
V(h,k) = (3,-5)

Use Quad. Formula and get:
X = 4.5,and 1.5. = X- Intercepts

To find Y-int.,replace x in given Eq
with 0 and solve for y.
Y-int = 4.

Answer 2

Correction: F(x) = Y = 2(x-3)^2-5

Use the following points for graphing:

(X,Y)
(1,3)
(2,-7)
V(3,-5)
(4,-3)
(5,3)

Answer 3

Correction: (2,-7) should be (2,-3).