I'd take f(1.5)-f(0.5)
the slope of the line passing through points near f(1) is probably pretty close to f'(1). As the two surrounding points get closer together, the slope more closely approximates f'(1).
if f(t) were continious on the interval [-2,1] but youo were only given the function for t=-2,-3/2,-1,-1/2 ..,3/2 and 2, explain how would you apporximate f'(1)
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