To find the remainder when \( f(x) = x^6 - 4x^3 + 2 \) is divided by \( x + 1 \), we can use the Remainder Theorem. This theorem states that the remainder of the division of a polynomial \( f(x) \) by \( x - a \) is \( f(a) \).
In this case, we want to divide by \( x + 1 \), or \( x - (-1) \). Therefore, we will evaluate \( f(-1) \):
\[ f(x) = x^6 - 4x^3 + 2 \]
Now, substituting \( -1 \) into \( f(x) \):
\[ f(-1) = (-1)^6 - 4(-1)^3 + 2 \] \[ = 1 - 4(-1) + 2 \] \[ = 1 + 4 + 2 \] \[ = 7 \]
Thus, the remainder when \( f(x) \) is divided by \( x + 1 \) is \( \boxed{7} \).