Asked by Jack Donald
If f is a function with domain [-11,13] and range (3,5].
What is the domain of f(6x+1)
And what is the range of 6f(x)+1
What is the domain of f(6x+1)
And what is the range of 6f(x)+1
Answers
Answered by
oobleck
since f is defined only on [-11,13], you need
-11 <= 6x+13 <= 13
-4 <= x <= 0
so the new domain is [-4,0]
the range of 6f(x) + 1 is (6*3+1,6*5+1] = (19,31]
-11 <= 6x+13 <= 13
-4 <= x <= 0
so the new domain is [-4,0]
the range of 6f(x) + 1 is (6*3+1,6*5+1] = (19,31]
Answered by
Jack Donald
Hi oobleck,
Your answer for the range of 6f(x)+1 is correct.
But unfortunately the calculation of the domain for f(6x+1) isn't. I'm still trying to find the answer myself, I'm not sure where I'm tripping up.
Your answer for the range of 6f(x)+1 is correct.
But unfortunately the calculation of the domain for f(6x+1) isn't. I'm still trying to find the answer myself, I'm not sure where I'm tripping up.
Answered by
oobleck
well, I guess you didn't catch my glaring typo!
-11 <= 6x+1 <= 13
-2 <= x < 2
so the domain is [-2,2]
-11 <= 6x+1 <= 13
-2 <= x < 2
so the domain is [-2,2]
Answered by
Jack Donald
Thanks!
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