If equal masses of Sodium and Strontium were reacted with excess hydrochloric acid, which experiment would produce a greater volume of hydrogen gas?

Answer 1

You have to start with balanced equation..

2Na+2HCl> 2NaCl + H2 or one mole Na gives 1/2 mole of H2
Sr +2HCl>SrCl2 + H2 so one mole of Sr gives one mole of H2

Now mass

let m be the mass

m/23 = moles of Na
m/38=mole Sr

amount of gas:
Sr: m/38
Na: m/23 (1/2)=m/46

well, m/38 is greater than m/46, so the answer is...