If each edge of a cube is increased by 2 inches, the

A. volume is increased by 8 cubic inches
B. area of each face is increased by 4 square inches
D. sum of the edges is increased by 24 inches

2 answers

try volume
Vnew = (x+2)(x+2)(x+2) big mess

try area
Anew = (x+2)(x+2) = x^2 + 4 x + 4
not this for sure

try that perimeter thing
how many edges?
4bottom +4top +4verticals = 12 edges
12 * 2 = 24 !!! winner
what's c?

I kind of have the same question and my c is that the diagonal of each face is increased by 2 inches. If you need me to disprove that then here you go

Let x represent the side.
Split the square into 2 triangles.
Using the special triangles we know it's a 45, 45, 90 because it's an isosceles triangle. Therefore the diagonal of the triangle before it was added by 2 would be x radical 2.

After you add 2 to all the sides the diagonal would be x+2 multiplied by radical 2 and it's not the same becuase you are technically distributing radical 2 to all the terms so it would be increased by 2 radical 2 instead of being increased by 2 inches