If (e^x)^-2 X (e^x)^2 X e^x = 1/e^2

find x?

I have no idea how to do this

2 answers

(e^x)^-2=1/(e^x)^2

(e^x)^-2*(e^x)^2*e^x=[1/(e^x)^2]*[(e^x)^2]*e^x=1/e^2

[1/(e^x)^2]*[(e^x)^2]=1

1*e^x=1/e^2

e^x=e^-2

ln(e^x)=ln(e^-2)

ln(e^x)=x

ln(e^-2)= -2

x= -2
Thank You so much!!
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