If e^f(x) = 1 + x^2, then f'(x) =

Answer 1

e^y = 1+x^2
e^y y' = 2x
y' = 2x/e^y = 2x/(1+x^2)

or, since e^y = 1+x^2
y = ln(1+x^2)
y' = 2x/(1+x^2)

Answer 2

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