y' = 6x^2 + 2
y = 2x^3 + 6x + C
since y(1) = 7,
2+6+C = 7
so
y = 2x^3 + 6x - 1
If dydx=6x2+2, find y given that y=7 when x=1.
2 answers
oops - dunno how 2x got changed to 6x
y = 2x^3 + 2x + 3
y = 2x^3 + 2x + 3
1 answer