y = ∫ ( 6 x² + 2 ) dx = 6 ∙ ∫ x² dx + 2 ∙ ∫ dx = 6 ∙ x³ / 3 + 2 x + C
y = 2 x³ + 2 x + C
y = 7 when x = 1 means:
7 = 2 ∙ 1³ + 2 ∙ 1 + C
7 = 2 + 2 + C
7 = 4 + C
7 - 4 = C
3 = C
C = 3
y = 2 x³ + 2 x + C
y = 2 x³ + 2 x + 3
If dydx=6x2+2, find y given that y=7 when x=1.
2 answers
This is correct if your expression dydx=6x2+2 means:
dy / dx= 6 x² + 2
dy / dx= 6 x² + 2