If dy/dx=(xy^2) and if y=1 when x=0, then when y=3, x is equal to
a) 1/8
b) - π/8
c) 1
d) (2√3)/3
2 answers
I have answer D
dy/dx=(xy^2) and if y=1 when x=0, then when y=3, x
dy/dx = xy^2
dy/y^2 = x dx
1/3 y^3 = 1/2 x^2 + C/3
y^3 = 3/2 x^2 + C
1 = 3/2 + C
C = -1/2
y^3 = 1/2 (3x^2-1)
3^3 = 1/2 (3x-1)
54 = 3x-1
x = 55/3
I think your answers are for a different problem.
dy/dx = xy^2
dy/y^2 = x dx
1/3 y^3 = 1/2 x^2 + C/3
y^3 = 3/2 x^2 + C
1 = 3/2 + C
C = -1/2
y^3 = 1/2 (3x^2-1)
3^3 = 1/2 (3x-1)
54 = 3x-1
x = 55/3
I think your answers are for a different problem.